Simpangan baku dari data 1,1,2,3,4,5,7,9

yakni

½√29
Pembahasan:
x︦ = 1 + 1 + 2 + 3 + 4 + 5 + 7 + 9
                          8
   = 32
       8
   = 4
S² = Σ(xi – x︦)²
= 2(1–4)² + (2–4)² + (3–4)² + (4–4)² + (5–4)² + (7–4)² + (9–4)² ÷ 8
= 18 + 4 + 1 + 0 + 1 + 9 + 25
                     8
= 58
     8
= 29
     4
S = √29 = ½√29
         4
  Diketahui matriks P = (2 5 1 3), Q = (2 3 0 1), maka PQ = ...