Komposisi (f ⚬ g)(x) =
x + 2/x – 1
Pembahasan:
(f ⚬ g)(x) = f(g(x))
= f( x )
x – 1
= 3( x ) _ 2
x – 1
= 3x _ 2(x – 1)
x – 1 x – 1
= 3x – (2x – 2)
x – 1
= x + 2
x – 1
Komposisi (f ⚬ g)(x) =
x + 2/x – 1