fungsi f : R → R dan g : R → R dirumuskan dengan f(x) = ½x – 1 dan g(x) = 2x + 4

by

Nilai (g ⚬ f)⁻¹(10) =

8
Pembahasan:
f(x) = ½x – 1
g(x) = 2x + 4
(g ⚬ f)(x) = g(f(x))
                = g(½x – 1)
                = 2(½x – 1) + 4
                = x + 2
Maka,  (g ⚬ f)⁻¹(x) = x – 2
 (g ⚬ f)⁻¹(10) = 10 – 2 = 8
  Kuartil, Desil, Simpangan Baku, Varian, dsb