hambatan pengganti antara titik a dan b

by

Diketahui:

begin mathsize 14px style R subscript 1 equals 6 space straight capital omega R subscript 2 equals 3 space straight capital omega R subscript 3 equals 6 space straight capital omega R subscript 4 equals 10 space straight capital omega R subscript 5 equals 12 space straight capital omega end style

Ditanyakan:

hambatan pengganti total  begin mathsize 14px style open parentheses R subscript t close parentheses end style

Jawab:

kendala pengganti pada rangkaian paralel begin mathsize 14px style R subscript 2 space & space R subscript 3 end style

begin mathsize 14px style 1 over R subscript p 1 end subscript equals 1 over R subscript 2 plus 1 over R subscript 3 1 over R subscript p 1 end subscript equals 1 third plus 1 over 6 1 over R subscript p 1 end subscript equals fraction numerator 2 plus 1 over denominator 6 end fraction 1 over R subscript p 1 end subscript equals 3 over 6 R subscript p 1 end subscript equals 6 over 3 R subscript p 1 end subscript equals 2 space straight capital omega end style

kendala pengganti pada rangkaian seri begin mathsize 14px style R subscript p 1 end subscript space & space R subscript 4 end style

begin mathsize 14px style R subscript s 1 end subscript equals R subscript p 1 end subscript plus R subscript 4 R subscript s 1 end subscript equals 2 plus 10 R subscript s 1 end subscript equals 12 space straight capital omega end style

hambatan pengganti pada rangkaian paralel begin mathsize 14px style R subscript s 1 end subscript space & space R subscript 5 end style

begin mathsize 14px style 1 over R subscript p 2 end subscript equals 1 over R subscript s 1 end subscript plus 1 over R subscript 5 1 over R subscript p 2 end subscript equals 1 over 12 plus 1 over 12 1 over R subscript p 2 end subscript equals 2 over 12 R subscript p 2 end subscript equals 12 over 2 R subscript p 2 end subscript equals 6 space straight capital omega end style

hambatan pengganti total (seri antara begin mathsize 14px style R subscript 1 space & space R subscript p 2 end subscript end style)

begin mathsize 14px style R subscript t equals R subscript 1 plus R subscript p 2 end subscript R subscript t equals 6 plus 6 R subscript t equals 12 space straight capital omega end style

Kaprikornus, jawaban yg sempurna yakni C.

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