Jika f(x) = 4√2x³ – 1 maka f'(1) 17/01/2023 by rizalhadizan yaitu 12 Pembahasan: f(x) = 4√2x³ – 1 f'(x) = 4 6x² 2√2x³ – 1 f'(1) = 4 . 6 . 1² 2√2.1³ – 1 = 24 2 = 12 Kuartil, Desil, Simpangan Baku, Varian, dsb