limit x mendekati 3 x² – 9/√x² + 16x – 5 17/01/2023 by rizalhadizan = 10 Pembahasan: lim x² – 9 x￫3 √x² + 16x – 5 = lim 2x/2x x￫3 2√x² + 16 = lim 2√x² + 16 x￫3 = 2√3² + 16 = 2√9 + 16 = 2√25 = 2 × 5 = 10 Jika f(x) = 4√2x³ – 1 maka f'(1)