Nilai dr 2log 4 + 2log 12
–2log 6 ialah…..
Jawaban:
3
Penjelasan dgn langkah-langkah:
[tex] ^ 2 log4 + \: ^ 2 log12 \: – ^ 2 log6 = ^ 2 log(4 \times 12 \div 6) \\ = \: ^ 2 log8 \\ = \: ^ 2 log2 \times 3 \\ = 3[/tex]
Nilai dr 2log 4 – 2log 6 + 2log 12 adalah
Bab Logaritma
Matematika SMA Kelas X
²log 4 – ²log 6 + ²log 12
= 2log 2² + ²log 12 – ²log 6
= 2 + ²log (12 : 6)
= 2 + ²log 2
= 2 + 1
= 3
Nilai dari
2log 4 +2log 12 – 2log 6 =..
2log4=2
2log12=2+2log3
2log6=1+2log3
2+2+2log3-1-2log3= 3
nilai dr 2log 4 + 2log 12+ 2log 6
²log 4.12.6
= ²log 288
= ² log12²×2
= 2.²log12 + ²log2
= 2.²log 4.3 +²log2
= 2.²log 4 + ²log3+ ²log2
=2.2+²log3+1
= 5+²log3
nilai dr 2log 4+2log 12-2log 6=…
²log 4 + ²log 12 – ²log 6 = ²log (4×12:6)
= ²log 8
= ²log 2³
= 3 ²log 2
= 3