Simpangan baku dari data 1,1,2,3,4,5,7,9

Pembahasan:

x︦ = 1 + 1 + 2 + 3 + 4 + 5 + 7 + 9

                          8

   = 32

       8

   = 4

S² = Σ(xi – x︦)²

= 2(1–4)² + (2–4)² + (3–4)² + (4–4)² + (5–4)² + (7–4)² + (9–4)² ÷ 8

= 18 + 4 + 1 + 0 + 1 + 9 + 25

                     8

= 58

     8

= 29

     4

S = √29 = ½√29

         4